-x^2+2=0

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-x^2+2=0
f(x)={x^2-2x,x>=0 x^2+2x,x

f(x)={x^2-2x,x>=0x^2+2x,xf(x)={x^2-2x,x>=0x^2+2x,xf(x)={x^2-2x,x>=0x^2+2x,x●奇偶函数的判定:奇函数:f(-x)=-f(x)偶

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已知x*x+x-1=0求x*x*x-2x+2010的值

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x(x-2)+x-2=0

x(x-2)+x-2=0x(x-2)+x-2=0x(x-2)+x-2=0x(x-2)+x-2=0x(x-2)+(x-2)=0x(x-2)+1×(x-2)=0(x+1)(x-2)=0x+1=0或x-2=

x(x-2)+x-2=0

x(x-2)+x-2=0x(x-2)+x-2=0x(x-2)+x-2=0x平方-2x+x-2=0(可省略)x平方-x-2=0(可省略)(x+1)(x-2)=0(若省略1、2步,则解释就是提公因式(x-

x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^20

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5/x^2+x - 1/x^2-x=0

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x/x-1-2x-2/x-1=0

x/x-1-2x-2/x-1=0x/x-1-2x-2/x-1=0x/x-1-2x-2/x-1=0x等于2

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(x-2)(x-4)+4x(x-3)=0

(x-2)(x-4)+4x(x-3)=0(x-2)(x-4)+4x(x-3)=0(x-2)(x-4)+4x(x-3)=0解(x-2)(x-4)+4x(x-3)=0x²-6x+8+4x

x(x+2)(x+6)+20x+6=0

x(x+2)(x+6)+20x+6=0x(x+2)(x+6)+20x+6=0x(x+2)(x+6)+20x+6=0x(1)=(38361^(1/2)/9+559/27)^(1/3)-32/(9*(38

(x+2)(x-3)(x-6)(x-1)=0

(x+2)(x-3)(x-6)(x-1)=0(x+2)(x-3)(x-6)(x-1)=0(x+2)(x-3)(x-6)(x-1)=0有种方法叫做穿针引线法,需要在纸上画出函数的简图,这个题的答案应该是

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x^2+x=0

x^2+x=0x^2+x=0x^2+x=0 

f(x)=-x^2+2x(x>0) 0(x=0) x^2-2x(x

f(x)=-x^2+2x(x>0)0(x=0)x^2-2x(xf(x)=-x^2+2x(x>0)0(x=0)x^2-2x(xf(x)=-x^2+2x(x>0)0(x=0)x^2-2x(x-1≤a-2≤

已知函数f(x)=-x^2+2X (X>0) 0(X=0) x^2-2X(X

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判断其奇偶性 f(x)={x(x-2) x≥ -x(x+2) x<0}f(x)={x(x-2) x≥

判断其奇偶性f(x)={x(x-2)x≥-x(x+2)x<0}f(x)={x(x-2)x≥0-x(x+2)x<0}判断其奇偶性f(x)={x(x-2)x≥-x(x+2)x<0}f(x)={x(x-2)