求arctan(2x/(2-x^2))的麦克劳林级数,∑ (n=0,正无穷)(-1)^(n/2)*x^2n+1/(2^n*(2n+1)),\x\

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求arctan(2x/(2-x^2))的麦克劳林级数,∑ (n=0,正无穷)(-1)^(n/2)*x^2n+1/(2^n*(2n+1)),\x\

求arctan(2x/(2-x^2))的麦克劳林级数,∑ (n=0,正无穷)(-1)^(n/2)*x^2n+1/(2^n*(2n+1)),\x\
求arctan(2x/(2-x^2))的麦克劳林级数,
∑ (n=0,正无穷)(-1)^(n/2)*x^2n+1/(2^n*(2n+1)),\x\

求arctan(2x/(2-x^2))的麦克劳林级数,∑ (n=0,正无穷)(-1)^(n/2)*x^2n+1/(2^n*(2n+1)),\x\
令t=2x/2-x^2 在x=0处的展开即等效为在t=0处展开
用arctan t 的麦克劳林展开式 然后将t=t(x)代回即可