解方程x(3x-4)-7=2(x^2-2)+2x

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解方程x(3x-4)-7=2(x^2-2)+2x
解方程x(3x-4)-7=2(x^2-2)+2x

解方程x(3x-4)-7=2(x^2-2)+2x
x(3x-4)-7=2(x^2-2)+2x
去括号得3x^2-4x-7=2x^2-4+2x
移项合并同类项得x^2-6x-3=0
配方得：(x-3)^2=12
两边同时开方得：x-3=±√12
x=3+2√3 或 x=3-2√3

x(3x-4)-7=2(x²-2)+2x
3x²-4x-7=2x²-4+2x
x²-6x=3
x²-6x+9=3+9
(x-3)²=12
x1=3+2√3 x2=3-2√3

答案是：x+2x^2=7

3x²－4x－7＝2x²－4＋2x
x²－6x－3＝0
﹙x－3﹚²＝12
x－3＝±√12
x1＝3＋2√3
x2＝3－2√3.

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