若实数x,y满足x²+y²-10x-2y+26=0 ,求根号下x²y²的值
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![若实数x,y满足x²+y²-10x-2y+26=0 ,求根号下x²y²的值](/uploads/image/z/3850669-37-9.jpg?t=%E8%8B%A5%E5%AE%9E%E6%95%B0x%2Cy%E6%BB%A1%E8%B6%B3x%26%23178%3B%2By%26%23178%3B-10x-2y%2B26%3D0+%2C%E6%B1%82%E6%A0%B9%E5%8F%B7%E4%B8%8Bx%26%23178%3By%26%23178%3B%E7%9A%84%E5%80%BC)
若实数x,y满足x²+y²-10x-2y+26=0 ,求根号下x²y²的值
若实数x,y满足x²+y²-10x-2y+26=0 ,求根号下x²y²的值
若实数x,y满足x²+y²-10x-2y+26=0 ,求根号下x²y²的值
x²-10x+y²-2y+26=0
(x-5)²=x²-10x+25
(x-5)(x-5)=x²-10x+25
(x-5)²+(y-1)²=0
x-5=0 y-1=0
x=5 y=1
求根号下x²y²=25
题出错了吧,是不是求根号下x²+y²的值
x²+y²-10x-2y+26=0
(X-5)^2+(y-1)^2=0
所以x=5,y=1 x²y²=25那个,能写详细点吗?本人水平低,实在是很费解……晕,任何数的平方都是大于或等于0的,即(x-5)^>=0 (y-1)^2>=0,由(X-5)^2+(y-1)^2=0可以知道,必须(x-5)^=0 (y-1)^2=0,才能是...
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x²+y²-10x-2y+26=0
(X-5)^2+(y-1)^2=0
所以x=5,y=1 x²y²=25
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