[(x+2y)²-(x+y)(x-y)-4y²]÷2y

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[(x+2y)²-(x+y)(x-y)-4y²]÷2y

[(x+2y)²-(x+y)(x-y)-4y²]÷2y
[(x+2y)²-(x+y)(x-y)-4y²]÷2y

[(x+2y)²-(x+y)(x-y)-4y²]÷2y
[(x+2y)²-(x+y)(x-y)-4y²]÷2y =[x^2+4xy+4y^2-(x^2-y^2)-4y^2]÷2y
=[x^2+4xy+4y^2-x^2+y^2-4y^2]÷2y
=[4xy+y^2]÷2y
=2x+y/2

这个很简单的
原式={(x+2y)^2-(2y)^2-(X^2-y^2)}/2y={(x+2y-2y)(x+2y+2y)-(X^2-y^2)}/2y=(y^2-4xy)/2y=y/2-2x