解不等式log(1/2)(x^2+2x-3)>log(1/2)(3x+1)

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解不等式log(1/2)(x^2+2x-3)>log(1/2)(3x+1)

解不等式log(1/2)(x^2+2x-3)>log(1/2)(3x+1)
解不等式log(1/2)(x^2+2x-3)>log(1/2)(3x+1)

解不等式log(1/2)(x^2+2x-3)>log(1/2)(3x+1)
由于 1/2

log(1/2)(x^2+2x-3)>log(1/2)(3x+1)
x^2+2x-3<3x+1
x^2-x-4<0
(x-1/2)^2<17/4
1/2-二分之根17

log(1/2)(x^2+2x-3)>log(1/2)(3x+1)
(x^2+2x-3)<(3x+1)
x^2-x-4<0, x^2-x-4=0
x=(1±√17)/2 , (1-√17)/2x^2+2x-3>0 , x<-3 ,x>1
3x+1>0 ,x>-1/3
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