已知a,b实数,且ab=1设p=a/a+1 +b/b+1.q=1/a+1 +1/b+1则pq=....已知a,b实数,且ab=1设p=(a/a+1) +b/(b+1).q=1/(a+1) +1/(b+1)则pq=

已知a,b实数,且ab=1设p=a/a+1 +b/b+1.q=1/a+1 +1/b+1则pq=....已知a,b实数,且ab=1设p=(a/a+1) +b/(b+1).q=1/(a+1) +1/(b+1)则pq=
已知a,b实数,且ab=1设p=a/a+1 +b/b+1.q=1/a+1 +1/b+1则pq=
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已知a,b实数,且ab=1设p=(a/a+1) +b/(b+1).q=1/(a+1) +1/(b+1)则pq=

已知a,b实数,且ab=1设p=a/a+1 +b/b+1.q=1/a+1 +1/b+1则pq=....已知a,b实数,且ab=1设p=(a/a+1) +b/(b+1).q=1/(a+1) +1/(b+1)则pq=
ab=1
b=1/a
带入p得
p=a/(a+1) + 1/a/(1/a + 1)
=a/(a+1) + 1/a/((1+a)/a)
=a/(a+1) + 1/(1+a)
=1
同理 q=1
pq=1

a

1

不懂，说清楚点。