解方程组(1):xy-y-2x+2=0 (2):x2-2x+y2-4x=-5方程组:xy-y-2x+2=0: x2-2x+y2-4x=-5怎么解?

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解方程组(1):xy-y-2x+2=0 (2):x2-2x+y2-4x=-5方程组:xy-y-2x+2=0:          x2-2x+y2-4x=-5怎么解?

解方程组(1):xy-y-2x+2=0 (2):x2-2x+y2-4x=-5方程组:xy-y-2x+2=0: x2-2x+y2-4x=-5怎么解?
解方程组(1):xy-y-2x+2=0 (2):x2-2x+y2-4x=-5
方程组:xy-y-2x+2=0
: x2-2x+y2-4x=-5
怎么解?

解方程组(1):xy-y-2x+2=0 (2):x2-2x+y2-4x=-5方程组:xy-y-2x+2=0: x2-2x+y2-4x=-5怎么解?
化简(1)得 y(x-1)=2(x-1) 然后分类讨论(因为要看x-1能不能直接两边同除) 当x=1时,根据(2)式算出y=0;当x不等于1时 y(x-1)=2(x-1) 就可以两边同除以(x-1)得y=2,代入(2)式可以算出x=3

xy-y-2x+2=0
x(y-2)-(y-2)=0
(x-1)(y-2)=0
x=1,y=2
x^2-2x+y^2-4x=-5
(x-1)^2+(y-2)^2=0
x=1,y=2