x+y=3,xy=-2,试求代数式(1)(x-y)²; (2) x的四次方+y的四次方的值.

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x+y=3,xy=-2,试求代数式(1)(x-y)²; (2) x的四次方+y的四次方的值.

x+y=3,xy=-2,试求代数式(1)(x-y)²; (2) x的四次方+y的四次方的值.
x+y=3,xy=-2,试求代数式(1)(x-y)²; (2) x的四次方+y的四次方的值.

x+y=3,xy=-2,试求代数式(1)(x-y)²; (2) x的四次方+y的四次方的值.
(1)(x-y)²
=x^2+y^2-2xy
=(x+y)^2-4xy
=3^2-4*(-2)
=9+8
=17
(2) x^4+y^4
=(x^2+y^2)^2-2x^2y^2
=[(x+y)^2-2xy]^2-2(xy)^2
=[3^2-2*(-2)]^2-2*(-2)^2
=(9+4)^2-8
=13^2-8
=169-8
=161

1、(x-y)²=x²-2xy+y²=(x²+2xy+y²)-4xy=(x+y)²-4xy=17;
2、x^4+y^4=(x²+y²)²-2(xy)²=17²-8=281

(x-y)²=(x+y)²-4xy=9+8=17
x的四次方+y的四次方=(x²+y²)²-2x²y²=((x+y)²-2xy)²-2x²y²=(9+4)²-2*4=161

(x-y)^2=x^2-2xy+y^2
x+y=3
(x+y)^2=x^+2xy+y^2=9
xy=-2
则,x^2+y^=13
所以(x-y)^2=13+4=17
x^4+y^4=(x^2)^2+(y^2)^2
=(x^2+y^2)^2-2x^2y^2
=[(x+y)^2-2xy]^2-2(xy)^2
=[(9+4)^2]-8
=169-8
=161