[1+2+3+4+5+...+2009+2010]/[(1-1/1006)(1-1/1007)...(1-1/2009)(1-1/2010)]

来源：学生作业帮助网编辑：作业帮时间：2024/04/28 00:32:31

[1+2+3+4+5+...+2009+2010]/[(1-1/1006)(1-1/1007)...(1-1/2009)(1-1/2010)]
[1+2+3+4+5+...+2009+2010]/[(1-1/1006)(1-1/1007)...(1-1/2009)(1-1/2010)]

[1+2+3+4+5+...+2009+2010]/[(1-1/1006)(1-1/1007)...(1-1/2009)(1-1/2010)]
[1+2+3+4+5+...+2009+2010]/[(1-1/1006)(1-1/1007)...(1-1/2009)(1-1/2010)]
=[(1+2010)*2010/2]/[(1005*1006*.*2009)/(1006*1007*.*2010)]
=[(1+2010)*2010/2]/(1005/2010)
=2021055/(1005/2010)
=4042110

=2011*2010/2*1005/1006*1006/1007...*2009/2010=2011*1005/2=1060802.5

[1+2+3+4+5+...+2009+2010]/[(1-1/1006)(1-1/1007)...(1-1/2009)(1-1/2010)]
=[（1+2010）×2010/2]/[1005/1006×1006/1007×...×2008/2009×2009/2010]
=2011×1005÷1005/2010
=4042110

1/2009+2/2009-3/2009-4/2009+5/2009+6/2009-7/2009-8/2009+9/2009+10/2009-...-1999/2009-2000/2009+2001/2009+2002/2009 (-1)+-2+(-3)+4+(-5)+...+(-2009)+2010 请问(2/2009+4/2009+6/2009+···+2008/2009)—(1/2009+3/2009+5/2009+···+2007/2009)等于多少? (1-2)(2-3)(3-4)(4-5)(5-6)……(2008-2009)(2009-2010) 1,2,3,2,3,4,3,4,5,4,5,6,.这列数中第2009个数是? 1,2,3,2,3,4,3,4,5,4,5,6第2009位数是多少 1-2+3-4+5-6...+2008-2009等于几? 1-2+3-4+5-6+.+2009-2010+2001 简算 (1+3+5+...+2009)-(2+4+6+...+2008)=? 1+2+3+4+5+6+.2009等于多少? 1-2+3-4+5-6+...+2007-2008-2009= 1-2+3-4+5-6.+2007-2008+2009-2010 1+2-3-4+5+6.+2009+2010 (2+4+6+.2010)—（1+3+5+.2009)= 1+2+3+4+5+...+2009+2010+2011等于多少 1-2-3+4+5-6-7+.+2009-2010 计算2013-2012+2010-2009+...+5-4+3-2+1 计算:(-1)+(+2)+(-3)+(+4)+(-5)+…+(-2009)+(+2010)