化简(x-1)(x+1)(x^2+1)(x^4+1)…(x^64+1)

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化简(x-1)(x+1)(x^2+1)(x^4+1)…(x^64+1)

化简(x-1)(x+1)(x^2+1)(x^4+1)…(x^64+1)
化简(x-1)(x+1)(x^2+1)(x^4+1)…(x^64+1)

化简(x-1)(x+1)(x^2+1)(x^4+1)…(x^64+1)
(x-1)(x+1)(x^2+1)(x^4+1)…(x^64+1)
=(x^2-1)(x^2+1)(x^4+1)…(x^64+1)
=(x^4-1)(x^4+1)…(x^64+1)
=(x^8-1)……(x^64+1)
=……
=x^128-1

应用平方差公式:(x-1)(x+1) = x^2-1
(x-1)(x+1)(x^2+1)=x^4-1
(x-1)(x+1)(x^2+1)(x^4+1)=x^8-1....
最后可得(x^64-1)(x^64+1)=x^128-1

(x-1)(x+1)(x^2+1)(x^4+1)(x^8+1)……(x^32+1)(x^64-1)
=(x^2-1)(x^2+1)(x^4+1)(x^8+1)……(x^32+1)(x^64-1)
=(x^64-1)^2

(a-1)(a+1)=a^2-1这个公式
一次类推。。最终答案应该是:x^128-1