(1+cos2x)/(sin2x-2sin^2 x)应如何化简?

(1+cos2x)/(sin2x-2sin^2 x)应如何化简?
(1+cos2x)/(sin2x-2sin^2 x)应如何化简?

(1+cos2x)/(sin2x-2sin^2 x)应如何化简?
利用倍角公式sin2A=2sinAcosA
cos2A=2(cosA)^2-1=1-2(sinA)^2
可以得到[1+2(cosA)^2-1]/[2sinAcosA-2(sin A)^2]
化简可得[(cosA)^2]/[sinAcosA-(sin A)^2]