6(2x+1)^2-13(2x+1)-15=0

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6(2x+1)^2-13(2x+1)-15=0

6(2x+1)^2-13(2x+1)-15=0
6(2x+1)^2-13(2x+1)-15=0

6(2x+1)^2-13(2x+1)-15=0
6(2x+1)²-13(2x+1)-15=0
6(4x²+4x+1)-26x-13-15=0
24x²+24x+6-26x-13-15=0
24x²-2x-22=0
12x²-x-11=0
(x-1)(12x+11)=0
x-1=0 12x+11=0
x1=1 x2=-11/2

设2x+1=A
原式=6A^2-13A-15=0
(6A+5)(A-3)=0
A1=-5/6 A2=3
x1=-11/12 x2=1


令2x+1=a

6a²-13a-15=0
1 -3
6 5
十字交叉
(a-3)(6a+5)=0
∴a=3,a=-5/6
∴2x+1=3或2x+1=-5/6
∴x=1或x=-11/12

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