[紧急求助]数学--化简:{(2n-1)×[(n-1)^2+1+n^2]}÷2注:…^2指…的二次方

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[紧急求助]数学--化简:{(2n-1)×[(n-1)^2+1+n^2]}÷2注:…^2指…的二次方

[紧急求助]数学--化简:{(2n-1)×[(n-1)^2+1+n^2]}÷2注:…^2指…的二次方
[紧急求助]数学--化简:{(2n-1)×[(n-1)^2+1+n^2]}÷2注:…^2指…的二次方

[紧急求助]数学--化简:{(2n-1)×[(n-1)^2+1+n^2]}÷2注:…^2指…的二次方
{(2n-1)×[(n-1)^2+1+n^2]}÷2
=[(2n-1)×(n²-2n+1+1+n²)]÷2
=[(2n-1)×(2n²-2n+2)]÷2
=[2(2n-1)×(n²-n+1)]÷2
=(2n-1)×(n²-n+1)
=2n³-2n²+2n-n²+n-1
=2n³-3n²+3n-1

等于:2n的三次方+3n-3n的二次方-1

是2n^3-3n^2+3n-1 吧!
希望对您有帮助!

原式={(2n-1)×[n^2-2n+1+1+n^2]}÷2
={(2n-1)×[2n^2-2n+2]}÷2
=(2n-1)×[n^2-n+1]
=2n^3-2n^2+2n-n^2+n-1
=2n^3-3n^2+3n-1
=n^3+(n-1)^3

{(2n-1)×[(n-1)^2+1+n^2]}÷2
={(2n-1)×[n^2-2n+1+1+n^2]}÷2
={(2n-1)×[2n^2-2n+2]}÷2
=(2n-1)×[n^2-n+1]
=2n^3-2n^2+2n-n^2+n-1
=2n^3-3n^2+3n-1
=n^3+(n-1)^3