log3 x=1 log16 64=x logx 1/5=-1/4 log32 x=7/5 logx 234=5/6 log125 1/25=x

来源：学生作业帮助网编辑：作业帮时间：2024/05/03 23:15:40

log3 x=1 log16 64=x logx 1/5=-1/4 log32 x=7/5 logx 234=5/6 log125 1/25=x
log3 x=1 log16 64=x logx 1/5=-1/4 log32 x=7/5 logx 234=5/6 log125 1/25=x

log3 x=1 log16 64=x logx 1/5=-1/4 log32 x=7/5 logx 234=5/6 log125 1/25=x
1,x=3^1=3
2,x=log[2^4] 2^6=6/4=1.5
3,1/四次根号x=1/5,所以,x=5^4=625
4,x=32^(7/5)=(2^5)^(7/5)=2^(5*7/5)=2^7=128
5,x^(5/6)=234,所以,x=234^(6/5)
6,x=log[5^3] 5^(-2)=-2/3
一般对于log[x^a] y^b=b/a*log[x] y

(1)x=3
(2)x=1.5
(3)x=625
(4)x=128
(5)x=234^(6/5)=696.7212054
(6)x=-2/3

log3 x=1 log16 64=x logx 1/5=-1/4 log32 x=7/5 logx 234=5/6 log125 1/25=x 已知log8(x+1)-log16(x+1)^3=1,求x的值. 已知log8(x+1)-log16(x+1)^3=1,求x的值. 若logx+log8=log16则x=?答案详尽 log3（2）+log3（x)=1,则X=? log3(2)+log3(x)=1,则x=? log3(x^2-3)=1+log3(x-5/3) log3(x-1)+log3(x+1)=1+log3(x+9)的解为 log3(3x-1)=log3(x-1)+log3(3+x)的解是如题关于对数函数log3 (x^2+2)=log3 x+1以log3为底 x属于[1/9,27],f(x)=log3(x/27)*log3(3x)的最大值解方程log7[log3（x)]=-1 logx 3=1/(log3 x)?为什么? 如果log3^(2x+1)=log3^(x^2-2)则x= 解方程log3 (9^x+8) = x+log3 (3^x+1 + 6) y=log3(9/x)×log3 3x求值域! log3(x-1)=log9(x+5) 求x log3(x-1)=log9(x-5) 求x