设f(x)=3ax^2+2bx+c,若a+b+c=0,f(0)>0,f(1)>0设f(x)=3ax^2+2bx+c,若a+b+c=0,f(0)>0,f(1)>0,求证:(Ⅰ)a>0且-2
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![设f(x)=3ax^2+2bx+c,若a+b+c=0,f(0)>0,f(1)>0设f(x)=3ax^2+2bx+c,若a+b+c=0,f(0)>0,f(1)>0,求证:(Ⅰ)a>0且-2](/uploads/image/z/1972228-4-8.jpg?t=%E8%AE%BEf%EF%BC%88x%EF%BC%89%3D3ax%5E2%2B2bx%2Bc%2C%E8%8B%A5a%2Bb%2Bc%3D0%2Cf%280%29%3E0%2Cf%281%29%3E0%E8%AE%BEf%EF%BC%88x%EF%BC%89%3D3ax%5E2%2B2bx%2Bc%2C%E8%8B%A5a%2Bb%2Bc%3D0%2Cf%EF%BC%880%EF%BC%89%3E0%2Cf%EF%BC%881%EF%BC%89%EF%BC%9E0%2C%E6%B1%82%E8%AF%81%3A%EF%BC%88%E2%85%A0%EF%BC%89a%3E0%E4%B8%94-2)
设f(x)=3ax^2+2bx+c,若a+b+c=0,f(0)>0,f(1)>0设f(x)=3ax^2+2bx+c,若a+b+c=0,f(0)>0,f(1)>0,求证:(Ⅰ)a>0且-2
设f(x)=3ax^2+2bx+c,若a+b+c=0,f(0)>0,f(1)>0
设f(x)=3ax^2+2bx+c,若a+b+c=0,f(0)>0,f(1)>0,求证:
(Ⅰ)a>0且-2
设f(x)=3ax^2+2bx+c,若a+b+c=0,f(0)>0,f(1)>0设f(x)=3ax^2+2bx+c,若a+b+c=0,f(0)>0,f(1)>0,求证:(Ⅰ)a>0且-2
1)
f(0)=c>0,f(1)=3a+2b+c>0
a+(2a+2b+2c)-c>0
a-c>0,a>c>0
b-2a,b/a>-2
b=-a-c
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