Y=In in in(x)求导

来源：学生作业帮助网编辑：作业帮时间：2024/05/10 05:43:30

Y=In in in(x)求导
Y=In in in(x)求导

Y=In in in(x)求导
y'=(lnlnln(x))'
=(lnlnx)'/lnln(x)
=(lnx)'/lnx*lnlnx
=1/xlnx*lnlnx

y' = 1/lnln(x) * 1/ln(x) *1/x
=1/xlnx（lnlnx）

y'=1/lnln(x)*(lnln(x))'=1/lnln(x)*1/(lnx)*(lnx)'=1/lnln(x)*1/(lnx)*1/x=1/(x*lnlnx*lnlnlnx)

y=lnu
u=lnv
v=lnx
易知，y′(u)=1/u.
u′(v)=1/v
v′(x)=1/x
又y'(x)=y'(u)u'(v)v'(x)
=(1/u)(1/v)(1/x)
=1/[(lnlnx)(xlnx)]

Y=In in in(x)求导 y=In(In^2(in^3x))求导 y=(x^2)*In(ex),求导? y=In √[(2x-1)/(x+1)],求导? y=in((1-x)/(1+x))求导求导y=cos[In(1+3x)] 文科:求导,y=IN(8+3x) 求导y=In|x|求大神帮助 X/y=In (xy ) 隐函数求导 y=In(x3+x)+x2+1怎么求导求导：y=In(secx+tanx) y=In(secx+tan2x)怎么求导求导y=In[In(Inx)]求具体过程 y=in(x+y)求导请问(x+y-1)中的-1是怎么来的求导y=cos[In(1+3x)]求具体过程. 一道复合导数题目,求教y=In根号x+根号Inx求导求导运算y=In(1+cosx)-[1/(1+cosx)] 求导In[(x+3)/3x]RT,In[(x+3)/3x]的求导!