作业帮c语言二维数组排序给定一个10*10的矩阵a,编一程序实现a[i1][j1]
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![c语言二维数组排序给定一个10*10的矩阵a,编一程序实现a[i1][j1]](/uploads/image/z/5480715-3-5.jpg?t=c%E8%AF%AD%E8%A8%80%E4%BA%8C%E7%BB%B4%E6%95%B0%E7%BB%84%E6%8E%92%E5%BA%8F%E7%BB%99%E5%AE%9A%E4%B8%80%E4%B8%AA10%2A10%E7%9A%84%E7%9F%A9%E9%98%B5a%2C%E7%BC%96%E4%B8%80%E7%A8%8B%E5%BA%8F%E5%AE%9E%E7%8E%B0a%5Bi1%5D%5Bj1%5D)
c语言二维数组排序给定一个10*10的矩阵a,编一程序实现a[i1][j1]
c语言二维数组排序
给定一个10*10的矩阵a,编一程序实现
a[i1][j1]
c语言二维数组排序给定一个10*10的矩阵a,编一程序实现a[i1][j1]
#include<stdio.h>
int main()
{
int a[100]={12,35,36,45,88,77,99,14,123,321,
78,98,58,52,54,56,575,59,15,222,
111,222,333,444,555,666,777,888,999,101,
22,33,44,55,66,75,48,49,94,91,93,
1,2,3,4,5,6,10,7,8,9,85,86,84,46,
145,146,147,148,149,150,154,156,157,
168,665,169,167,125,123,124,126,127,
49,995,458,645,198,197,196,194,129,556,
213,214,215,219,216,228,227,225,226,
445,446,447,448,449,450,452,453};
int b[10][10];
int i,j,k,e;
for(i=0;i<100;i++)
for(j=0;j<100-i;j++)
{
if(a[j]>a[j+1])
{e=a[j];a[j]=a[j+1];a[j+1]=e;}
}
k=0;
for(i=0;i<10;i++)
for(j=0;j<10;j++)
{b[i][j]=a[k];k++;}
for(i=0;i<10;i++)
{ for(j=0;j<10;j++)
printf("%-4d",b[i][j]);
printf("\n");}
printf("\n");
return 0;
}
是这样吧?希望能帮助你!（望采纳）