如何用for循环编写最好是c,c#语言n=1 时y=sin(1)*x1n=2 y=sin(1/2)*x1+sin(2/2)*x2n=3 y=sin(1/3)*x1+sin(2/3)*x2+sin(3/3)*x3;n=4 y=sin(1/4)*x1+sin(2/4)*x2+sin(3/4)*x3+sin(4/4)*x4;...n=n y=sin(1/n)*x1+sin(2/n)*x2+.sin(n/n)*xn;x1-xn的值是分
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![如何用for循环编写最好是c,c#语言n=1 时y=sin(1)*x1n=2 y=sin(1/2)*x1+sin(2/2)*x2n=3 y=sin(1/3)*x1+sin(2/3)*x2+sin(3/3)*x3;n=4 y=sin(1/4)*x1+sin(2/4)*x2+sin(3/4)*x3+sin(4/4)*x4;...n=n y=sin(1/n)*x1+sin(2/n)*x2+.sin(n/n)*xn;x1-xn的值是分](/uploads/image/z/5577364-28-4.jpg?t=%E5%A6%82%E4%BD%95%E7%94%A8for%E5%BE%AA%E7%8E%AF%E7%BC%96%E5%86%99%E6%9C%80%E5%A5%BD%E6%98%AFc%2Cc%23%E8%AF%AD%E8%A8%80n%3D1+%E6%97%B6y%3Dsin%281%29%2Ax1n%3D2+y%3Dsin%281%2F2%29%2Ax1%2Bsin%282%2F2%29%2Ax2n%3D3+y%3Dsin%281%2F3%29%2Ax1%2Bsin%282%2F3%29%2Ax2%2Bsin%283%2F3%29%2Ax3%3Bn%3D4+y%3Dsin%281%2F4%29%2Ax1%2Bsin%282%2F4%29%2Ax2%2Bsin%283%2F4%29%2Ax3%2Bsin%284%2F4%29%2Ax4%3B...n%3Dn+y%3Dsin%281%2Fn%29%2Ax1%2Bsin%282%2Fn%29%2Ax2%2B.sin%28n%2Fn%29%2Axn%3Bx1-xn%E7%9A%84%E5%80%BC%E6%98%AF%E5%88%86)
如何用for循环编写最好是c,c#语言n=1 时y=sin(1)*x1n=2 y=sin(1/2)*x1+sin(2/2)*x2n=3 y=sin(1/3)*x1+sin(2/3)*x2+sin(3/3)*x3;n=4 y=sin(1/4)*x1+sin(2/4)*x2+sin(3/4)*x3+sin(4/4)*x4;...n=n y=sin(1/n)*x1+sin(2/n)*x2+.sin(n/n)*xn;x1-xn的值是分
如何用for循环编写最好是c,c#语言
n=1 时y=sin(1)*x1
n=2 y=sin(1/2)*x1+sin(2/2)*x2
n=3 y=sin(1/3)*x1+sin(2/3)*x2+sin(3/3)*x3;
n=4 y=sin(1/4)*x1+sin(2/4)*x2+sin(3/4)*x3+sin(4/4)*x4;
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n=n y=sin(1/n)*x1+sin(2/n)*x2+.sin(n/n)*xn;
x1-xn的值是分别是1,2,3.N
求y值
如何用for循环编写最好是c,c#语言n=1 时y=sin(1)*x1n=2 y=sin(1/2)*x1+sin(2/2)*x2n=3 y=sin(1/3)*x1+sin(2/3)*x2+sin(3/3)*x3;n=4 y=sin(1/4)*x1+sin(2/4)*x2+sin(3/4)*x3+sin(4/4)*x4;...n=n y=sin(1/n)*x1+sin(2/n)*x2+.sin(n/n)*xn;x1-xn的值是分
double _result=0.0f;
int n=100;
int [] x=new int [100];//需要初始化
for(int _Num=1;_Num