怎么证明tan(π/(2k+1))×tan(2π/(2k+1))×tan(3π/(2k+1))×.tan(k/(2k+1))=根号(2k+1)k为正整数)当k=1时,即tan(π/3)=根号3当k=2时,即tan(π/5)×tan(2π/5)=根号5.

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怎么证明tan(π/(2k+1))×tan(2π/(2k+1))×tan(3π/(2k+1))×.tan(k/(2k+1))=根号(2k+1)k为正整数)当k=1时,即tan(π/3)=根号3当k=2时,即tan(π/5)×tan(2π/5)=根号5.

怎么证明tan(π/(2k+1))×tan(2π/(2k+1))×tan(3π/(2k+1))×.tan(k/(2k+1))=根号(2k+1)k为正整数)当k=1时,即tan(π/3)=根号3当k=2时,即tan(π/5)×tan(2π/5)=根号5.
怎么证明tan(π/(2k+1))×tan(2π/(2k+1))×tan(3π/(2k+1))×.tan(k/(2k+1))=根号(2k+1)
k为正整数)
当k=1时,即tan(π/3)=根号3
当k=2时,即tan(π/5)×tan(2π/5)=根号5
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怎么证明tan(π/(2k+1))×tan(2π/(2k+1))×tan(3π/(2k+1))×.tan(k/(2k+1))=根号(2k+1)k为正整数)当k=1时,即tan(π/3)=根号3当k=2时,即tan(π/5)×tan(2π/5)=根号5.
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